3(t+6)+4(2t-4)=68

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Solution for 3(t+6)+4(2t-4)=68 equation: 



3(t+6)+4(2t-4)=68

We move all terms to the left:

3(t+6)+4(2t-4)-(68)=0

We multiply parentheses

3t+8t+18-16-68=0

We add all the numbers together, and all the variables

11t-66=0

We move all terms containing t to the left, all other terms to the right

11t=66

t=66/11

t=6

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