3(t+6)+7(t+1)=5(2t+5)

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Solution for 3(t+6)+7(t+1)=5(2t+5) equation: 



3(t+6)+7(t+1)=5(2t+5)

We move all terms to the left:

3(t+6)+7(t+1)-(5(2t+5))=0

We multiply parentheses

3t+7t-(5(2t+5))+18+7=0



We calculate terms in parentheses: -(5(2t+5)), so:

5(2t+5)

We multiply parentheses

10t+25

Back to the equation:

-(10t+25)



We add all the numbers together, and all the variables

10t-(10t+25)+25=0

We get rid of parentheses

10t-10t-25+25=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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