3(t-1)+t=2(t-1)

Solution for 3(t-1)+t=2(t-1) equation:

3(t-1)+t=2(t-1)

We move all terms to the left:

3(t-1)+t-(2(t-1))=0

We add all the numbers together, and all the variables

t+3(t-1)-(2(t-1))=0

We multiply parentheses

t+3t-(2(t-1))-3=0


We calculate terms in parentheses: -(2(t-1)), so:

2(t-1)

We multiply parentheses

2t-2

Back to the equation:

-(2t-2)


We add all the numbers together, and all the variables

4t-(2t-2)-3=0

We get rid of parentheses

4t-2t+2-3=0

We add all the numbers together, and all the variables

2t-1=0

We move all terms containing t to the left, all other terms to the right

2t=1

t=1/2

t=1/2