3(t-1)-2(2t-3)=5

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Solution for 3(t-1)-2(2t-3)=5 equation: 



3(t-1)-2(2t-3)=5

We move all terms to the left:

3(t-1)-2(2t-3)-(5)=0

We multiply parentheses

3t-4t-3+6-5=0

We add all the numbers together, and all the variables

-1t-2=0

We move all terms containing t to the left, all other terms to the right

-t=2

t=2/-1

t=-2

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