3(t-1)-2(t+2)=10(3t-4)

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Solution for 3(t-1)-2(t+2)=10(3t-4) equation: 



3(t-1)-2(t+2)=10(3t-4)

We move all terms to the left:

3(t-1)-2(t+2)-(10(3t-4))=0

We multiply parentheses

3t-2t-(10(3t-4))-3-4=0



We calculate terms in parentheses: -(10(3t-4)), so:

10(3t-4)

We multiply parentheses

30t-40

Back to the equation:

-(30t-40)



We add all the numbers together, and all the variables

t-(30t-40)-7=0

We get rid of parentheses

t-30t+40-7=0

We add all the numbers together, and all the variables

-29t+33=0

We move all terms containing t to the left, all other terms to the right

-29t=-33

t=-33/-29

t=1+4/29

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