3(t-1)-2(t+3)=5(t+3)

Solution for 3(t-1)-2(t+3)=5(t+3) equation:

3(t-1)-2(t+3)=5(t+3)

We move all terms to the left:

3(t-1)-2(t+3)-(5(t+3))=0

We multiply parentheses

3t-2t-(5(t+3))-3-6=0


We calculate terms in parentheses: -(5(t+3)), so:

5(t+3)

We multiply parentheses

5t+15

Back to the equation:

-(5t+15)


We add all the numbers together, and all the variables

t-(5t+15)-9=0

We get rid of parentheses

t-5t-15-9=0

We add all the numbers together, and all the variables

-4t-24=0

We move all terms containing t to the left, all other terms to the right

-4t=24

t=24/-4

t=-6