3(t-1)=(9+t)

Solution for 3(t-1)=(9+t) equation:

3(t-1)=(9+t)

We move all terms to the left:

3(t-1)-((9+t))=0

We add all the numbers together, and all the variables

3(t-1)-((t+9))=0

We multiply parentheses

3t-((t+9))-3=0


We calculate terms in parentheses: -((t+9)), so:

(t+9)

We get rid of parentheses

t+9

Back to the equation:

-(t+9)


We get rid of parentheses

3t-t-9-3=0

We add all the numbers together, and all the variables

2t-12=0

We move all terms containing t to the left, all other terms to the right

2t=12

t=12/2

t=6