3(t-2)+2t=13-t

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Solution for 3(t-2)+2t=13-t equation: 



3(t-2)+2t=13-t

We move all terms to the left:

3(t-2)+2t-(13-t)=0

We add all the numbers together, and all the variables

3(t-2)+2t-(-1t+13)=0

We add all the numbers together, and all the variables

2t+3(t-2)-(-1t+13)=0

We multiply parentheses

2t+3t-(-1t+13)-6=0

We get rid of parentheses

2t+3t+1t-13-6=0

We add all the numbers together, and all the variables

6t-19=0

We move all terms containing t to the left, all other terms to the right

6t=19

t=19/6

t=3+1/6

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