3(t-2)+3=(2t-3)

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Solution for 3(t-2)+3=(2t-3) equation: 



3(t-2)+3=(2t-3)

We move all terms to the left:

3(t-2)+3-((2t-3))=0

We multiply parentheses

3t-((2t-3))-6+3=0



We calculate terms in parentheses: -((2t-3)), so:

(2t-3)

We get rid of parentheses

2t-3

Back to the equation:

-(2t-3)



We add all the numbers together, and all the variables

3t-(2t-3)-3=0

We get rid of parentheses

3t-2t+3-3=0

We add all the numbers together, and all the variables

t=0

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