3(t-2)+3=3(2t-3)

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Solution for 3(t-2)+3=3(2t-3) equation:



3(t-2)+3=3(2t-3)
We move all terms to the left:
3(t-2)+3-(3(2t-3))=0
We multiply parentheses
3t-(3(2t-3))-6+3=0
We calculate terms in parentheses: -(3(2t-3)), so:
3(2t-3)
We multiply parentheses
6t-9
Back to the equation:
-(6t-9)
We add all the numbers together, and all the variables
3t-(6t-9)-3=0
We get rid of parentheses
3t-6t+9-3=0
We add all the numbers together, and all the variables
-3t+6=0
We move all terms containing t to the left, all other terms to the right
-3t=-6
t=-6/-3
t=+2

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