3(t-2)+3=3(2t-4)=

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Solution for 3(t-2)+3=3(2t-4)= equation: 



3(t-2)+3=3(2t-4)=

We move all terms to the left:

3(t-2)+3-(3(2t-4))=0

We multiply parentheses

3t-(3(2t-4))-6+3=0



We calculate terms in parentheses: -(3(2t-4)), so:

3(2t-4)

We multiply parentheses

6t-12

Back to the equation:

-(6t-12)



We add all the numbers together, and all the variables

3t-(6t-12)-3=0

We get rid of parentheses

3t-6t+12-3=0

We add all the numbers together, and all the variables

-3t+9=0

We move all terms containing t to the left, all other terms to the right

-3t=-9

t=-9/-3

t=+3

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