3(t-2)+3=3(2t-5)

Solution for 3(t-2)+3=3(2t-5) equation:

3(t-2)+3=3(2t-5)

We move all terms to the left:

3(t-2)+3-(3(2t-5))=0

We multiply parentheses

3t-(3(2t-5))-6+3=0


We calculate terms in parentheses: -(3(2t-5)), so:

3(2t-5)

We multiply parentheses

6t-15

Back to the equation:

-(6t-15)


We add all the numbers together, and all the variables

3t-(6t-15)-3=0

We get rid of parentheses

3t-6t+15-3=0

We add all the numbers together, and all the variables

-3t+12=0

We move all terms containing t to the left, all other terms to the right

-3t=-12

t=-12/-3

t=+4