3(t-2)/5+10=20

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Solution for 3(t-2)/5+10=20 equation: 



3(t-2)/5+10=20

We move all terms to the left:

3(t-2)/5+10-(20)=0

We add all the numbers together, and all the variables

3(t-2)/5-10=0

We multiply all the terms by the denominator


3(t-2)-10*5=0

We add all the numbers together, and all the variables

3(t-2)-50=0

We multiply parentheses

3t-6-50=0

We add all the numbers together, and all the variables

3t-56=0

We move all terms containing t to the left, all other terms to the right

3t=56

t=56/3

t=18+2/3

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