3(t-2)=2(2t-10)

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Solution for 3(t-2)=2(2t-10) equation: 



3(t-2)=2(2t-10)

We move all terms to the left:

3(t-2)-(2(2t-10))=0

We multiply parentheses

3t-(2(2t-10))-6=0



We calculate terms in parentheses: -(2(2t-10)), so:

2(2t-10)

We multiply parentheses

4t-20

Back to the equation:

-(4t-20)



We get rid of parentheses

3t-4t+20-6=0

We add all the numbers together, and all the variables

-1t+14=0

We move all terms containing t to the left, all other terms to the right

-t=-14

t=-14/-1

t=+14

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