3(t-2)=4(t+1)

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Solution for 3(t-2)=4(t+1) equation: 



3(t-2)=4(t+1)

We move all terms to the left:

3(t-2)-(4(t+1))=0

We multiply parentheses

3t-(4(t+1))-6=0



We calculate terms in parentheses: -(4(t+1)), so:

4(t+1)

We multiply parentheses

4t+4

Back to the equation:

-(4t+4)



We get rid of parentheses

3t-4t-4-6=0

We add all the numbers together, and all the variables

-1t-10=0

We move all terms containing t to the left, all other terms to the right

-t=10

t=10/-1

t=-10

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