3(t-2)=5(2t+1)

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Solution for 3(t-2)=5(2t+1) equation: 



3(t-2)=5(2t+1)

We move all terms to the left:

3(t-2)-(5(2t+1))=0

We multiply parentheses

3t-(5(2t+1))-6=0



We calculate terms in parentheses: -(5(2t+1)), so:

5(2t+1)

We multiply parentheses

10t+5

Back to the equation:

-(10t+5)



We get rid of parentheses

3t-10t-5-6=0

We add all the numbers together, and all the variables

-7t-11=0

We move all terms containing t to the left, all other terms to the right

-7t=11

t=11/-7

t=-1+4/7

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