3(t-24)=7-4(t-18)

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Solution for 3(t-24)=7-4(t-18) equation: 



3(t-24)=7-4(t-18)

We move all terms to the left:

3(t-24)-(7-4(t-18))=0

We multiply parentheses

3t-(7-4(t-18))-72=0



We calculate terms in parentheses: -(7-4(t-18)), so:

7-4(t-18)

determiningTheFunctionDomain
-4(t-18)+7

We multiply parentheses

-4t+72+7

We add all the numbers together, and all the variables

-4t+79

Back to the equation:

-(-4t+79)



We get rid of parentheses

3t+4t-79-72=0

We add all the numbers together, and all the variables

7t-151=0

We move all terms containing t to the left, all other terms to the right

7t=151

t=151/7

t=21+4/7

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