3(t-24)=9t-4(t+15)

Solution for 3(t-24)=9t-4(t+15) equation:

3(t-24)=9t-4(t+15)

We move all terms to the left:

3(t-24)-(9t-4(t+15))=0

We multiply parentheses

3t-(9t-4(t+15))-72=0


We calculate terms in parentheses: -(9t-4(t+15)), so:

9t-4(t+15)

We multiply parentheses

9t-4t-60

We add all the numbers together, and all the variables

5t-60

Back to the equation:

-(5t-60)


We get rid of parentheses

3t-5t+60-72=0

We add all the numbers together, and all the variables

-2t-12=0

We move all terms containing t to the left, all other terms to the right

-2t=12

t=12/-2

t=-6