3(t-3)=5(2t+1)+5(3t-4)

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Solution for 3(t-3)=5(2t+1)+5(3t-4) equation: 



3(t-3)=5(2t+1)+5(3t-4)

We move all terms to the left:

3(t-3)-(5(2t+1)+5(3t-4))=0

We multiply parentheses

3t-(5(2t+1)+5(3t-4))-9=0



We calculate terms in parentheses: -(5(2t+1)+5(3t-4)), so:

5(2t+1)+5(3t-4)

We multiply parentheses

10t+15t+5-20

We add all the numbers together, and all the variables

25t-15

Back to the equation:

-(25t-15)



We get rid of parentheses

3t-25t+15-9=0

We add all the numbers together, and all the variables

-22t+6=0

We move all terms containing t to the left, all other terms to the right

-22t=-6

t=-6/-22

t=3/11

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