3(t-3)=5(2t+1)-12

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Solution for 3(t-3)=5(2t+1)-12 equation: 



3(t-3)=5(2t+1)-12

We move all terms to the left:

3(t-3)-(5(2t+1)-12)=0

We multiply parentheses

3t-(5(2t+1)-12)-9=0



We calculate terms in parentheses: -(5(2t+1)-12), so:

5(2t+1)-12

We multiply parentheses

10t+5-12

We add all the numbers together, and all the variables

10t-7

Back to the equation:

-(10t-7)



We get rid of parentheses

3t-10t+7-9=0

We add all the numbers together, and all the variables

-7t-2=0

We move all terms containing t to the left, all other terms to the right

-7t=2

t=2/-7

t=-2/7

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