3(t-3)=5(2t+2)

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Solution for 3(t-3)=5(2t+2) equation: 



3(t-3)=5(2t+2)

We move all terms to the left:

3(t-3)-(5(2t+2))=0

We multiply parentheses

3t-(5(2t+2))-9=0



We calculate terms in parentheses: -(5(2t+2)), so:

5(2t+2)

We multiply parentheses

10t+10

Back to the equation:

-(10t+10)



We get rid of parentheses

3t-10t-10-9=0

We add all the numbers together, and all the variables

-7t-19=0

We move all terms containing t to the left, all other terms to the right

-7t=19

t=19/-7

t=-2+5/7

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