3(t-3)=5(2t+t)

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Solution for 3(t-3)=5(2t+t) equation: 



3(t-3)=5(2t+t)

We move all terms to the left:

3(t-3)-(5(2t+t))=0

We add all the numbers together, and all the variables

3(t-3)-(5(+3t))=0

We multiply parentheses

3t-(5(+3t))-9=0



We calculate terms in parentheses: -(5(+3t)), so:

5(+3t)

We multiply parentheses

15t

Back to the equation:

-(15t)



We add all the numbers together, and all the variables

-12t-9=0

We move all terms containing t to the left, all other terms to the right

-12t=9

t=9/-12

t=-3/4

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