3(t-4)+7t=5(2t+2)-8

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Solution for 3(t-4)+7t=5(2t+2)-8 equation: 


Simplifying
3(t + -4) + 7t = 5(2t + 2) + -8

Reorder the terms:
3(-4 + t) + 7t = 5(2t + 2) + -8
(-4 * 3 + t * 3) + 7t = 5(2t + 2) + -8
(-12 + 3t) + 7t = 5(2t + 2) + -8

Combine like terms: 3t + 7t = 10t
-12 + 10t = 5(2t + 2) + -8

Reorder the terms:
-12 + 10t = 5(2 + 2t) + -8
-12 + 10t = (2 * 5 + 2t * 5) + -8
-12 + 10t = (10 + 10t) + -8

Reorder the terms:
-12 + 10t = 10 + -8 + 10t

Combine like terms: 10 + -8 = 2
-12 + 10t = 2 + 10t

Add '-10t' to each side of the equation.
-12 + 10t + -10t = 2 + 10t + -10t

Combine like terms: 10t + -10t = 0
-12 + 0 = 2 + 10t + -10t
-12 = 2 + 10t + -10t

Combine like terms: 10t + -10t = 0
-12 = 2 + 0
-12 = 2

Solving
-12 = 2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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