3(t-4)+7t=5(2t+5)-10

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Solution for 3(t-4)+7t=5(2t+5)-10 equation:


Simplifying
3(t + -4) + 7t = 5(2t + 5) + -10

Reorder the terms:
3(-4 + t) + 7t = 5(2t + 5) + -10
(-4 * 3 + t * 3) + 7t = 5(2t + 5) + -10
(-12 + 3t) + 7t = 5(2t + 5) + -10

Combine like terms: 3t + 7t = 10t
-12 + 10t = 5(2t + 5) + -10

Reorder the terms:
-12 + 10t = 5(5 + 2t) + -10
-12 + 10t = (5 * 5 + 2t * 5) + -10
-12 + 10t = (25 + 10t) + -10

Reorder the terms:
-12 + 10t = 25 + -10 + 10t

Combine like terms: 25 + -10 = 15
-12 + 10t = 15 + 10t

Add '-10t' to each side of the equation.
-12 + 10t + -10t = 15 + 10t + -10t

Combine like terms: 10t + -10t = 0
-12 + 0 = 15 + 10t + -10t
-12 = 15 + 10t + -10t

Combine like terms: 10t + -10t = 0
-12 = 15 + 0
-12 = 15

Solving
-12 = 15

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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