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3(t-4)-(2t+3)=-4
We move all terms to the left:
3(t-4)-(2t+3)-(-4)=0
We add all the numbers together, and all the variables
3(t-4)-(2t+3)+4=0
We multiply parentheses
3t-(2t+3)-12+4=0
We get rid of parentheses
3t-2t-3-12+4=0
We add all the numbers together, and all the variables
t-11=0
We move all terms containing t to the left, all other terms to the right
t=11
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