3(t-4)=-2(t+3(=18

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Solution for 3(t-4)=-2(t+3(=18 equation: 



3(t-4)=-2(t+3(=18

We move all terms to the left:

3(t-4)-(-2(t+3()=0

We multiply parentheses

3t-(-2(t+3()-12=0

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