3(t-4)=-2(t-5)=10

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Solution for 3(t-4)=-2(t-5)=10 equation: 



3(t-4)=-2(t-5)=10

We move all terms to the left:

3(t-4)-(-2(t-5))=0

We multiply parentheses

3t-(-2(t-5))-12=0



We calculate terms in parentheses: -(-2(t-5)), so:

-2(t-5)

We multiply parentheses

-2t+10

Back to the equation:

-(-2t+10)



We get rid of parentheses

3t+2t-10-12=0

We add all the numbers together, and all the variables

5t-22=0

We move all terms containing t to the left, all other terms to the right

5t=22

t=22/5

t=4+2/5

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