3(t-4)=2t+t-12

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Solution for 3(t-4)=2t+t-12 equation: 


Simplifying
3(t + -4) = 2t + t + -12

Reorder the terms:
3(-4 + t) = 2t + t + -12
(-4 * 3 + t * 3) = 2t + t + -12
(-12 + 3t) = 2t + t + -12

Reorder the terms:
-12 + 3t = -12 + 2t + t

Combine like terms: 2t + t = 3t
-12 + 3t = -12 + 3t

Add '12' to each side of the equation.
-12 + 12 + 3t = -12 + 12 + 3t

Combine like terms: -12 + 12 = 0
0 + 3t = -12 + 12 + 3t
3t = -12 + 12 + 3t

Combine like terms: -12 + 12 = 0
3t = 0 + 3t
3t = 3t

Add '-3t' to each side of the equation.
3t + -3t = 3t + -3t

Combine like terms: 3t + -3t = 0
0 = 3t + -3t

Combine like terms: 3t + -3t = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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