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3(t-4)=5(2-t)
We move all terms to the left:
3(t-4)-(5(2-t))=0
We add all the numbers together, and all the variables
3(t-4)-(5(-1t+2))=0
We multiply parentheses
3t-(5(-1t+2))-12=0
We calculate terms in parentheses: -(5(-1t+2)), so:We get rid of parentheses
5(-1t+2)
We multiply parentheses
-5t+10
Back to the equation:
-(-5t+10)
3t+5t-10-12=0
We add all the numbers together, and all the variables
8t-22=0
We move all terms containing t to the left, all other terms to the right
8t=22
t=22/8
t=2+3/4
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