3(t-40)=-(t-20)

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Solution for 3(t-40)=-(t-20) equation: 



3(t-40)=-(t-20)

We move all terms to the left:

3(t-40)-(-(t-20))=0

We multiply parentheses

3t-(-(t-20))-120=0



We calculate terms in parentheses: -(-(t-20)), so:

-(t-20)

We get rid of parentheses

-t+20

We add all the numbers together, and all the variables

-1t+20

Back to the equation:

-(-1t+20)



We get rid of parentheses

3t+1t-20-120=0

We add all the numbers together, and all the variables

4t-140=0

We move all terms containing t to the left, all other terms to the right

4t=140

t=140/4

t=35

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