3(t-5)+7t=5(2t+4)-12

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Solution for 3(t-5)+7t=5(2t+4)-12 equation:


Simplifying
3(t + -5) + 7t = 5(2t + 4) + -12

Reorder the terms:
3(-5 + t) + 7t = 5(2t + 4) + -12
(-5 * 3 + t * 3) + 7t = 5(2t + 4) + -12
(-15 + 3t) + 7t = 5(2t + 4) + -12

Combine like terms: 3t + 7t = 10t
-15 + 10t = 5(2t + 4) + -12

Reorder the terms:
-15 + 10t = 5(4 + 2t) + -12
-15 + 10t = (4 * 5 + 2t * 5) + -12
-15 + 10t = (20 + 10t) + -12

Reorder the terms:
-15 + 10t = 20 + -12 + 10t

Combine like terms: 20 + -12 = 8
-15 + 10t = 8 + 10t

Add '-10t' to each side of the equation.
-15 + 10t + -10t = 8 + 10t + -10t

Combine like terms: 10t + -10t = 0
-15 + 0 = 8 + 10t + -10t
-15 = 8 + 10t + -10t

Combine like terms: 10t + -10t = 0
-15 = 8 + 0
-15 = 8

Solving
-15 = 8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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