3(t-6)+2=4(t+2)-2-

Solution for 3(t-6)+2=4(t+2)-2- equation:

3(t-6)+2=4(t+2)-2-

We move all terms to the left:

3(t-6)+2-(4(t+2)-2-)=0

We multiply parentheses

3t-(4(t+2)-2-)-18+2=0


We calculate terms in parentheses: -(4(t+2)-2-), so:

4(t+2)-2-

We add all the numbers together, and all the variables

4(t+2)

We multiply parentheses

4t+8

Back to the equation:

-(4t+8)


We add all the numbers together, and all the variables

3t-(4t+8)-16=0

We get rid of parentheses

3t-4t-8-16=0

We add all the numbers together, and all the variables

-1t-24=0

We move all terms containing t to the left, all other terms to the right

-t=24

t=24/-1

t=-24