3(t-9)-4(6-3t)=14(t-5)-2

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Solution for 3(t-9)-4(6-3t)=14(t-5)-2 equation: 



3(t-9)-4(6-3t)=14(t-5)-2

We move all terms to the left:

3(t-9)-4(6-3t)-(14(t-5)-2)=0

We add all the numbers together, and all the variables

3(t-9)-4(-3t+6)-(14(t-5)-2)=0

We multiply parentheses

3t+12t-(14(t-5)-2)-27-24=0



We calculate terms in parentheses: -(14(t-5)-2), so:

14(t-5)-2

We multiply parentheses

14t-70-2

We add all the numbers together, and all the variables

14t-72

Back to the equation:

-(14t-72)



We add all the numbers together, and all the variables

15t-(14t-72)-51=0

We get rid of parentheses

15t-14t+72-51=0

We add all the numbers together, and all the variables

t+21=0

We move all terms containing t to the left, all other terms to the right

t=-21

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