3(u+1)(u-1)=0

Solution for 3(u+1)(u-1)=0 equation:

Simplifying
3(u + 1)(u + -1) = 0

Reorder the terms:
3(1 + u)(u + -1) = 0

Reorder the terms:
3(1 + u)(-1 + u) = 0

Multiply (1 + u) * (-1 + u)
3(1(-1 + u) + u(-1 + u)) = 0
3((-1 * 1 + u * 1) + u(-1 + u)) = 0
3((-1 + 1u) + u(-1 + u)) = 0
3(-1 + 1u + (-1 * u + u * u)) = 0
3(-1 + 1u + (-1u + u2)) = 0

Combine like terms: 1u + -1u = 0
3(-1 + 0 + u2) = 0
3(-1 + u2) = 0
(-1 * 3 + u2 * 3) = 0
(-3 + 3u2) = 0

Solving
-3 + 3u2 = 0

Solving for variable 'u'.

Move all terms containing u to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 3u2 = 0 + 3

Combine like terms: -3 + 3 = 0
0 + 3u2 = 0 + 3
3u2 = 0 + 3

Combine like terms: 0 + 3 = 3
3u2 = 3

Divide each side by '3'.
u2 = 1

Simplifying
u2 = 1

Take the square root of each side:
u = {-1, 1}