3(u+1)+1=19

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Solution for 3(u+1)+1=19 equation: 



3(u+1)+1=19

We move all terms to the left:

3(u+1)+1-(19)=0

We add all the numbers together, and all the variables

3(u+1)-18=0

We multiply parentheses

3u+3-18=0

We add all the numbers together, and all the variables

3u-15=0

We move all terms containing u to the left, all other terms to the right

3u=15

u=15/3

u=5

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