3(u+1)+2u=5(u+1)+5

Solution for 3(u+1)+2u=5(u+1)+5 equation:

Simplifying
3(u + 1) + 2u = 5(u + 1) + 5

Reorder the terms:
3(1 + u) + 2u = 5(u + 1) + 5
(1 * 3 + u * 3) + 2u = 5(u + 1) + 5
(3 + 3u) + 2u = 5(u + 1) + 5

Combine like terms: 3u + 2u = 5u
3 + 5u = 5(u + 1) + 5

Reorder the terms:
3 + 5u = 5(1 + u) + 5
3 + 5u = (1 * 5 + u * 5) + 5
3 + 5u = (5 + 5u) + 5

Reorder the terms:
3 + 5u = 5 + 5 + 5u

Combine like terms: 5 + 5 = 10
3 + 5u = 10 + 5u

Add '-5u' to each side of the equation.
3 + 5u + -5u = 10 + 5u + -5u

Combine like terms: 5u + -5u = 0
3 + 0 = 10 + 5u + -5u
3 = 10 + 5u + -5u

Combine like terms: 5u + -5u = 0
3 = 10 + 0
3 = 10

Solving
3 = 10

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.