3(u+2)+4=4(u+1)+10

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Solution for 3(u+2)+4=4(u+1)+10 equation: 



3(u+2)+4=4(u+1)+10

We move all terms to the left:

3(u+2)+4-(4(u+1)+10)=0

We multiply parentheses

3u-(4(u+1)+10)+6+4=0



We calculate terms in parentheses: -(4(u+1)+10), so:

4(u+1)+10

We multiply parentheses

4u+4+10

We add all the numbers together, and all the variables

4u+14

Back to the equation:

-(4u+14)



We add all the numbers together, and all the variables

3u-(4u+14)+10=0

We get rid of parentheses

3u-4u-14+10=0

We add all the numbers together, and all the variables

-1u-4=0

We move all terms containing u to the left, all other terms to the right

-u=4

u=4/-1

u=-4

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