3(u+2)+4=5(-1)+u

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Solution for 3(u+2)+4=5(-1)+u equation: 



3(u+2)+4=5(-1)+u

We move all terms to the left:

3(u+2)+4-(5(-1)+u)=0

We multiply parentheses

3u-(5(-1)+u)+6+4=0



We calculate terms in parentheses: -(5(-1)+u), so:

5(-1)+u

determiningTheFunctionDomain
u+5(-1)

We add all the numbers together, and all the variables

u-5

Back to the equation:

-(u-5)



We add all the numbers together, and all the variables

3u-(u-5)+10=0

We get rid of parentheses

3u-u+5+10=0

We add all the numbers together, and all the variables

2u+15=0

We move all terms containing u to the left, all other terms to the right

2u=-15

u=-15/2

u=-7+1/2

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