3(u+2)+u=4(u-1)+10

Solution for 3(u+2)+u=4(u-1)+10 equation:

Simplifying
3(u + 2) + u = 4(u + -1) + 10

Reorder the terms:
3(2 + u) + u = 4(u + -1) + 10
(2 * 3 + u * 3) + u = 4(u + -1) + 10
(6 + 3u) + u = 4(u + -1) + 10

Combine like terms: 3u + u = 4u
6 + 4u = 4(u + -1) + 10

Reorder the terms:
6 + 4u = 4(-1 + u) + 10
6 + 4u = (-1 * 4 + u * 4) + 10
6 + 4u = (-4 + 4u) + 10

Reorder the terms:
6 + 4u = -4 + 10 + 4u

Combine like terms: -4 + 10 = 6
6 + 4u = 6 + 4u

Add '-6' to each side of the equation.
6 + -6 + 4u = 6 + -6 + 4u

Combine like terms: 6 + -6 = 0
0 + 4u = 6 + -6 + 4u
4u = 6 + -6 + 4u

Combine like terms: 6 + -6 = 0
4u = 0 + 4u
4u = 4u

Add '-4u' to each side of the equation.
4u + -4u = 4u + -4u

Combine like terms: 4u + -4u = 0
0 = 4u + -4u

Combine like terms: 4u + -4u = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.