3(u+2)+u=4(u-1)+9

Solution for 3(u+2)+u=4(u-1)+9 equation:

Simplifying
3(u + 2) + u = 4(u + -1) + 9

Reorder the terms:
3(2 + u) + u = 4(u + -1) + 9
(2 * 3 + u * 3) + u = 4(u + -1) + 9
(6 + 3u) + u = 4(u + -1) + 9

Combine like terms: 3u + u = 4u
6 + 4u = 4(u + -1) + 9

Reorder the terms:
6 + 4u = 4(-1 + u) + 9
6 + 4u = (-1 * 4 + u * 4) + 9
6 + 4u = (-4 + 4u) + 9

Reorder the terms:
6 + 4u = -4 + 9 + 4u

Combine like terms: -4 + 9 = 5
6 + 4u = 5 + 4u

Add '-4u' to each side of the equation.
6 + 4u + -4u = 5 + 4u + -4u

Combine like terms: 4u + -4u = 0
6 + 0 = 5 + 4u + -4u
6 = 5 + 4u + -4u

Combine like terms: 4u + -4u = 0
6 = 5 + 0
6 = 5

Solving
6 = 5

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.