3(u+2)+u=4(u-1)=10

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Solution for 3(u+2)+u=4(u-1)=10 equation: 



3(u+2)+u=4(u-1)=10

We move all terms to the left:

3(u+2)+u-(4(u-1))=0

We add all the numbers together, and all the variables

u+3(u+2)-(4(u-1))=0

We multiply parentheses

u+3u-(4(u-1))+6=0



We calculate terms in parentheses: -(4(u-1)), so:

4(u-1)

We multiply parentheses

4u-4

Back to the equation:

-(4u-4)



We add all the numbers together, and all the variables

4u-(4u-4)+6=0

We get rid of parentheses

4u-4u+4+6=0

We add all the numbers together, and all the variables

10!=0

There is no solution for this equation

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