3(u+2)-2=2(u-1)+5

Solution for 3(u+2)-2=2(u-1)+5 equation:

Simplifying
3(u + 2) + -2 = 2(u + -1) + 5

Reorder the terms:
3(2 + u) + -2 = 2(u + -1) + 5
(2 * 3 + u * 3) + -2 = 2(u + -1) + 5
(6 + 3u) + -2 = 2(u + -1) + 5

Reorder the terms:
6 + -2 + 3u = 2(u + -1) + 5

Combine like terms: 6 + -2 = 4
4 + 3u = 2(u + -1) + 5

Reorder the terms:
4 + 3u = 2(-1 + u) + 5
4 + 3u = (-1 * 2 + u * 2) + 5
4 + 3u = (-2 + 2u) + 5

Reorder the terms:
4 + 3u = -2 + 5 + 2u

Combine like terms: -2 + 5 = 3
4 + 3u = 3 + 2u

Solving
4 + 3u = 3 + 2u

Solving for variable 'u'.

Move all terms containing u to the left, all other terms to the right.

Add '-2u' to each side of the equation.
4 + 3u + -2u = 3 + 2u + -2u

Combine like terms: 3u + -2u = 1u
4 + 1u = 3 + 2u + -2u

Combine like terms: 2u + -2u = 0
4 + 1u = 3 + 0
4 + 1u = 3

Add '-4' to each side of the equation.
4 + -4 + 1u = 3 + -4

Combine like terms: 4 + -4 = 0
0 + 1u = 3 + -4
1u = 3 + -4

Combine like terms: 3 + -4 = -1
1u = -1

Divide each side by '1'.
u = -1

Simplifying
u = -1