3(u+2)-4=2(u-1)+5

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Solution for 3(u+2)-4=2(u-1)+5 equation: 



3(u+2)-4=2(u-1)+5

We move all terms to the left:

3(u+2)-4-(2(u-1)+5)=0

We multiply parentheses

3u-(2(u-1)+5)+6-4=0



We calculate terms in parentheses: -(2(u-1)+5), so:

2(u-1)+5

We multiply parentheses

2u-2+5

We add all the numbers together, and all the variables

2u+3

Back to the equation:

-(2u+3)



We add all the numbers together, and all the variables

3u-(2u+3)+2=0

We get rid of parentheses

3u-2u-3+2=0

We add all the numbers together, and all the variables

u-1=0

We move all terms containing u to the left, all other terms to the right

u=1

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