3(u+2)-u=2(u-1)+5

Solution for 3(u+2)-u=2(u-1)+5 equation:

Simplifying
3(u + 2) + -1u = 2(u + -1) + 5

Reorder the terms:
3(2 + u) + -1u = 2(u + -1) + 5
(2 * 3 + u * 3) + -1u = 2(u + -1) + 5
(6 + 3u) + -1u = 2(u + -1) + 5

Combine like terms: 3u + -1u = 2u
6 + 2u = 2(u + -1) + 5

Reorder the terms:
6 + 2u = 2(-1 + u) + 5
6 + 2u = (-1 * 2 + u * 2) + 5
6 + 2u = (-2 + 2u) + 5

Reorder the terms:
6 + 2u = -2 + 5 + 2u

Combine like terms: -2 + 5 = 3
6 + 2u = 3 + 2u

Add '-2u' to each side of the equation.
6 + 2u + -2u = 3 + 2u + -2u

Combine like terms: 2u + -2u = 0
6 + 0 = 3 + 2u + -2u
6 = 3 + 2u + -2u

Combine like terms: 2u + -2u = 0
6 = 3 + 0
6 = 3

Solving
6 = 3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.