3(u+2)-u=4+2(u+1)

Solution for 3(u+2)-u=4+2(u+1) equation:

Simplifying
3(u + 2) + -1u = 4 + 2(u + 1)

Reorder the terms:
3(2 + u) + -1u = 4 + 2(u + 1)
(2 * 3 + u * 3) + -1u = 4 + 2(u + 1)
(6 + 3u) + -1u = 4 + 2(u + 1)

Combine like terms: 3u + -1u = 2u
6 + 2u = 4 + 2(u + 1)

Reorder the terms:
6 + 2u = 4 + 2(1 + u)
6 + 2u = 4 + (1 * 2 + u * 2)
6 + 2u = 4 + (2 + 2u)

Combine like terms: 4 + 2 = 6
6 + 2u = 6 + 2u

Add '-6' to each side of the equation.
6 + -6 + 2u = 6 + -6 + 2u

Combine like terms: 6 + -6 = 0
0 + 2u = 6 + -6 + 2u
2u = 6 + -6 + 2u

Combine like terms: 6 + -6 = 0
2u = 0 + 2u
2u = 2u

Add '-2u' to each side of the equation.
2u + -2u = 2u + -2u

Combine like terms: 2u + -2u = 0
0 = 2u + -2u

Combine like terms: 2u + -2u = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.