3(u+2)-u=6+2(u+1)

Solution for 3(u+2)-u=6+2(u+1) equation:

3(u+2)-u=6+2(u+1)

We move all terms to the left:

3(u+2)-u-(6+2(u+1))=0

We add all the numbers together, and all the variables

-1u+3(u+2)-(6+2(u+1))=0

We multiply parentheses

-1u+3u-(6+2(u+1))+6=0


We calculate terms in parentheses: -(6+2(u+1)), so:

6+2(u+1)

determiningTheFunctionDomain
2(u+1)+6

We multiply parentheses

2u+2+6

We add all the numbers together, and all the variables

2u+8

Back to the equation:

-(2u+8)


We add all the numbers together, and all the variables

2u-(2u+8)+6=0

We get rid of parentheses

2u-2u-8+6=0

We add all the numbers together, and all the variables

-2!=0

There is no solution for this equation