3(u+2)=+4=5(u-1)+u

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Solution for 3(u+2)=+4=5(u-1)+u equation: 



3(u+2)=+4=5(u-1)+u

We move all terms to the left:

3(u+2)-(+4)=0

We add all the numbers together, and all the variables

3(u+2)-4=0

We multiply parentheses

3u+6-4=0

We add all the numbers together, and all the variables

3u+2=0

We move all terms containing u to the left, all other terms to the right

3u=-2

u=-2/3

u=-2/3

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