3(u+2)=4(u-1)+10

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Solution for 3(u+2)=4(u-1)+10 equation: 



3(u+2)=4(u-1)+10

We move all terms to the left:

3(u+2)-(4(u-1)+10)=0

We multiply parentheses

3u-(4(u-1)+10)+6=0



We calculate terms in parentheses: -(4(u-1)+10), so:

4(u-1)+10

We multiply parentheses

4u-4+10

We add all the numbers together, and all the variables

4u+6

Back to the equation:

-(4u+6)



We get rid of parentheses

3u-4u-6+6=0

We add all the numbers together, and all the variables

-u=0

u=0/-1

u=0

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