3(u+3)=-2(9u-6)+9u

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Solution for 3(u+3)=-2(9u-6)+9u equation: 



3(u+3)=-2(9u-6)+9u

We move all terms to the left:

3(u+3)-(-2(9u-6)+9u)=0

We multiply parentheses

3u-(-2(9u-6)+9u)+9=0



We calculate terms in parentheses: -(-2(9u-6)+9u), so:

-2(9u-6)+9u

We add all the numbers together, and all the variables

9u-2(9u-6)

We multiply parentheses

9u-18u+12

We add all the numbers together, and all the variables

-9u+12

Back to the equation:

-(-9u+12)



We get rid of parentheses

3u+9u-12+9=0

We add all the numbers together, and all the variables

12u-3=0

We move all terms containing u to the left, all other terms to the right

12u=3

u=3/12

u=1/4

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