3(u+3)=2(8u-2)+4u

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Solution for 3(u+3)=2(8u-2)+4u equation:



3(u+3)=2(8u-2)+4u
We move all terms to the left:
3(u+3)-(2(8u-2)+4u)=0
We multiply parentheses
3u-(2(8u-2)+4u)+9=0
We calculate terms in parentheses: -(2(8u-2)+4u), so:
2(8u-2)+4u
We add all the numbers together, and all the variables
4u+2(8u-2)
We multiply parentheses
4u+16u-4
We add all the numbers together, and all the variables
20u-4
Back to the equation:
-(20u-4)
We get rid of parentheses
3u-20u+4+9=0
We add all the numbers together, and all the variables
-17u+13=0
We move all terms containing u to the left, all other terms to the right
-17u=-13
u=-13/-17
u=13/17

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