3(u+3)=2(8u-2)+4u

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Solution for 3(u+3)=2(8u-2)+4u equation: 



3(u+3)=2(8u-2)+4u

We move all terms to the left:

3(u+3)-(2(8u-2)+4u)=0

We multiply parentheses

3u-(2(8u-2)+4u)+9=0



We calculate terms in parentheses: -(2(8u-2)+4u), so:

2(8u-2)+4u

We add all the numbers together, and all the variables

4u+2(8u-2)

We multiply parentheses

4u+16u-4

We add all the numbers together, and all the variables

20u-4

Back to the equation:

-(20u-4)



We get rid of parentheses

3u-20u+4+9=0

We add all the numbers together, and all the variables

-17u+13=0

We move all terms containing u to the left, all other terms to the right

-17u=-13

u=-13/-17

u=13/17

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